Inventory balance equation. The constraint that says that the
amount of inventory in the next time period must equal the current
inventory plus what is produced or purchased minus what is lost or
sold. Let y(t) = inventory at the beginning of period t, with y(0)
given. Then, the inventory equation is:
y(t+1) = ay(t) + P(t) - S(t),
where P(t) = level of production (or somehow acquired), and
S(t) = level of sales (or somehow consumed). Typically, a=1, but if
a < 1, it is called a loss factor, and if a > 1, it is
called a gain factor.
The language used is for the inventory control in the
production scheduling
problem, but this has become a standard system of equations that
appears in many mathematical programs. Thus, the meaning of
the variables can be very different. One example is the
steel beam assortment
problem.
Inventory control problem. See
production scheduling problem.
Inverse problem. Given a point in the decision
space,
find parameter values that render it optimal. For example, suppose we
have an LP:
min{cx: Ax=b, x >= 0}. Let B be a basis from A, and we ask for
the values of (b, c) for which this basis is optimal. This has a
simple solution. Let A = [B N] and partition c and x conformally,
so Ax = BxB + NxN and
cx = cBxB + cNxN.
Then, the set of (b, c) for which the associated
basic solution is optimal
is the following cone:
KB = {(b, c): B–1b >= 0 and
cBB–1N <= cN}
A more difficult inverse problem is when there is some target value
for the parameters. We might, for example, fix b and seek to
minimize ||c–c*||², subject to (b, c) in KB,
where c* is a target value for c.
The problem can be combinatorial. We might want to minimize
||c–c*|| for some norm
for c's are costs on the arcs or
edges of a network. The solution at hand might be a
spanning tree
or a TSP tour.
We might also impose constraints on c directly, such as simple
bounds.
The general inverse problem may thus be stated:
min ||p – p*||: p in P and
p in argmin{f(x; p): x in F(p)},